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(D) The modal class is the class interval with the highest frequency. Since the mode is $140$,which lies in the interval $100-150$,the modal class is

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$36$

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(D) The modal class is the class interval with the highest frequency. Since the mode is $140$,which lies in the interval $100-150$,the modal class is $100-150$.The formula for mode is:$Mode = L + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} ight) 	imes h$Where:$L = 100$ (lower limit of modal class)$f_1 = 37$ (frequency of modal class)$f_0 = 33$ (frequency of class preceding modal class)$f_2 = b$ (frequency of class succeeding modal class)$h = 50$ (class size)Substituting the values:$140 = 100 + \left( \frac{37 - 33}{2(37) - 33 - b} ight) 	imes 50$$40 = \left( \frac{4}{74 - 33 - b} ight) 	imes 50$$40 = \frac{200}{41 - b}$$40(41 - b) = 200$$41 - b = 5$$b = 41 - 5 = 36$

Expenditure in $Rs. (x)$	$0-50$	$50-100$	$100-150$	$150-200$	$200-250$
No. of families $(f)$	$24$	$33$	$37$	$b$	$25$

$x_i$	$2$	$4$	$6$	$8$	$10$	$12$	$14$	$16$
$f_i$	$4$	$4$	$\alpha$	$15$	$8$	$\beta$	$4$	$5$

The frequency distribution of daily working expenditure of families in a locality is as follows:

Expenditure in $Rs. (x)$ $0-50$ $50-100$ $100-150$ $150-200$ $200-250$

No. of families $(f)$ $24$ $33$ $37$ $b$ $25$

If the mode of the distribution is $Rs. 140$,then the value of $b$ is:

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The frequency distribution of daily working expenditure of families in a locality is as follows: Expenditure in $Rs. (x)$ $0-50$ $50-100$ $100-150$ $150-200$ $200-250$ No. of families $(f)$ $24$ $33$ $37$ $b$ $25$ If the mode of the distribution is $Rs. 140$,then the value of $b$ is: